Introduction to solving joint variation:
Joint variation is like a direct variation in this it has two or more variables. The variables which are in right side of the equal sign vary equally. The value of the dependent variable increases when the values of the independent variable increases and the value of the dependent variable decreases when the value of the independent variable decreases. Having problem with Type of Functions keep reading my upcoming posts, i will try to help you.
General Form – Solving Joint Variation:
The general form of the joint variation is y = kxz , where k is a constant and x and z are variables.
Example Problems – Solving Joint Variation:
Example 1 – Solving joint variation:
Identify whether the given expression a=kbc is joint variation with the values b=2, c=3 and b=4 and c=5 with k = 1.
Solution:
The given expression is `a= kbc` .
Now substitute the given values in the given expression
When `b` =2 and `c` = 3 then `a` = `1*2*3 ` `=>` `a` = `6` .
When `b` = 4 and `c` = 5 then `a` = `1*4*5` `=>` `a` = `20`
When the value of `b` and `c` jointly directly varies then the value of `a` also varies directly. Please express your views of this topic Least Common Multiple Definition by commenting on blog.
Example 2 – Solving joint variation:
Identify whether the given expression y=kxz is joint variation with the values x =5, z=6 and x=6 and z = 7 with k = 2.
Solution:
The given expression is `y=kxz.`
Now substitute the given values in the given expression
When `x` =5 and `z` = 6 then `y` = `2*5*6` `=>` ` y` = `60` .
When `x` = 6 and `z` = 7 then `y` = `2*6*7` `=>`` y` = `84`
When the value of x and z jointly directly varies then the value of y also varies directly.
Example 3 – Solving joint variation:
Find the value of constant for the equation a=kbc where a = 3, b=4 and c = 1.
Solution:
The given expression is `a = kbc`
Now the above expression can be written as `k` = `a/(bc)`
`k` = `a/(bc)`
`k ` = `3/(4*1)`
`k` = `3/4`
`k` = 0.75
The value of `k` is 0.75.
Example 4 – Solving joint variation:
Find the value of z for the equation y = kxz where k = 3, y=4 and x = 1.
Solution:
The given expression is `y = kxz`
Now the above expression can be written as `z` = `y/(kx)`
`z` = `y/(kx)`
`z` = `4/(3*1)`
`z ` = `4/3`
`z` = `1.33`
Joint variation is like a direct variation in this it has two or more variables. The variables which are in right side of the equal sign vary equally. The value of the dependent variable increases when the values of the independent variable increases and the value of the dependent variable decreases when the value of the independent variable decreases. Having problem with Type of Functions keep reading my upcoming posts, i will try to help you.
General Form – Solving Joint Variation:
The general form of the joint variation is y = kxz , where k is a constant and x and z are variables.
Example Problems – Solving Joint Variation:
Example 1 – Solving joint variation:
Identify whether the given expression a=kbc is joint variation with the values b=2, c=3 and b=4 and c=5 with k = 1.
Solution:
The given expression is `a= kbc` .
Now substitute the given values in the given expression
When `b` =2 and `c` = 3 then `a` = `1*2*3 ` `=>` `a` = `6` .
When `b` = 4 and `c` = 5 then `a` = `1*4*5` `=>` `a` = `20`
When the value of `b` and `c` jointly directly varies then the value of `a` also varies directly. Please express your views of this topic Least Common Multiple Definition by commenting on blog.
Example 2 – Solving joint variation:
Identify whether the given expression y=kxz is joint variation with the values x =5, z=6 and x=6 and z = 7 with k = 2.
Solution:
The given expression is `y=kxz.`
Now substitute the given values in the given expression
When `x` =5 and `z` = 6 then `y` = `2*5*6` `=>` ` y` = `60` .
When `x` = 6 and `z` = 7 then `y` = `2*6*7` `=>`` y` = `84`
When the value of x and z jointly directly varies then the value of y also varies directly.
Example 3 – Solving joint variation:
Find the value of constant for the equation a=kbc where a = 3, b=4 and c = 1.
Solution:
The given expression is `a = kbc`
Now the above expression can be written as `k` = `a/(bc)`
`k` = `a/(bc)`
`k ` = `3/(4*1)`
`k` = `3/4`
`k` = 0.75
The value of `k` is 0.75.
Example 4 – Solving joint variation:
Find the value of z for the equation y = kxz where k = 3, y=4 and x = 1.
Solution:
The given expression is `y = kxz`
Now the above expression can be written as `z` = `y/(kx)`
`z` = `y/(kx)`
`z` = `4/(3*1)`
`z ` = `4/3`
`z` = `1.33`
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