Practice Vinculum

Introduction to Practice Vinculum:

Mathematical symbol which is used for grouping the mathematical expression is known as vinculum. A horizontal bar below the numerator and over the denominator is said to be vinculum. Vinculum is in the form of fraction, radical or in the parenthesis. For example, the mathematical expression `x + y - z` is expressed as `x + (y - z)` in the parenthesis form. Students practice the problems of vinculum with simple solutions to solve. Let us see about practice vinculum in this article. Having problem with Simplifying Rational Expressions Calculator keep reading my upcoming posts, i will try to help you.

General Format for Practice Vinculum

The format for vinculum is

In the form of fraction `(a + b)/ (a - b)`
In the form of radical is `sqrt(a - b)`
In the form of parentheses is `((a + b))/ ((a - b)) `
Worked Examples to Practice Vinculum

Example 1 to Practice Vinculum:

Solve the arithmetic expression `(27 + 37)/ (13 - 5)` .

Solution:

Step 1:

Given arithmetic expression is `(27 + 37)/ (13 - 5)` .

Step 2:

Solve the numerator and denominator of the expression, we get,

Adding the numerator, we get,

`27 + 37 = 64`

Subtracting the denominator, we get,

`13 - 5 = 8`

Step 3:

Dividing the fraction by placing the numerator and denominator, we get,

`64/8 = 8`

Step 4:

Dividing the fraction we get 8.

Hence, the solution for solving the vinculum is 8.

Example 2 to Practice Vinculum:

Solve the arithmetic expression `(36 + 6)/ (12 - 10)` .

Solution:

Step 1:

Given arithmetic expression is `(18 + 6)/ (12 - 9)` .

Step 2:

Solve the numerator and denominator of the expression, we get,

Adding the numerator, we get,

`18 + 6 = 24`

Subtracting the denominator, we get,

`12 - 9 = 3`

Step 3:

Dividing the fraction by placing the numerator and denominator, we get,

`24/3 = 8`

Step 4:

Dividing the fraction we get 8.

Hence, the solution for solving the vinculum is 8.

Example 3 to Practice Vinculum:

Solve the arithmetic expression `sqrt(27 + 22)` .

Solution:

Step 1:

Given arithmetic expression is `sqrt(27 + 22)` .

Step 2:

Solve the above expression, we get,

Adding the expression, we get,

`sqrt(49)`

Step 3:

Taking square root we get,

`sqrt(49) = 7`

Step 4:

Hence, the solution for solving the vinculum is 7. Please express your views of this topic free math problems for kids by commenting on blog.

Practice Problems to Practice Vinculum

Problem 1:

Solve the arithmetic expression `(23 + 4)/ (16 - 7)` .

Problem 2:

Solve the arithmetic expression `sqrt(109 + 12)` .

Solutions:

1. 3

2. 11