Tuesday, May 21, 2013

Math Practice Fourth Grade

Introduction to math practice fourth grade:

Here we are going to see the problems on math practice fourth grade; it covers some topics of the grade 4 Number sense ,Addition ,Subtraction ,Multiplication, Division ,Mixed operation ,Algebra ,Functions, statistics .In these topics we are going to see the practice problem with answers


Number sense math practice fourth grade


1) How do write this number   using digits?

Seventy nine

A) 7.90

B) 790

C) 0.79

D) 79

Addition- math practice fourth grade:

2) Add 4890and 567

Using the addition operation to do the above problem

A) 4812

B) 5457

C) 4702

D) 5902

subtraction- math practice fourth grade:

3) Subtract 6892and 5263

Using the subtraction  operation to do the above problem

A) 2529

B) 7890

C) 1629

D) 1529

Multiplication- math practice fourth grade:

4) Multiplication facts to 18

Multiply

18*12

A) 158

B) 216

C) 138

D) 197

Division - math practice fourth grade:

5) Fill the mixing number

5X /25=5

A) 25

B) 35

C) 125

D) 45

Algebra- math practice fourth grade:

6) Write an expression for 67 divided by 8

A) `67*8`

B) `67/8`

C) 67-8

D) 67+8

Mixed operation - math practice fourth grades:

7)John and his friend jolly went together to the department store for buy the chocolate, john bought 15 chocolates and jolly bought 4 chocolates ,about how many pieces of chocolates did they buy in all ?choose the better estimation.

A) 20

B) 15

C) 4

D) 11

Statistics - math practice fourth grades:

8) Find the median for the following numbers 7, 9,6,4,5,2,11

A) 4

B) 5

C) 6

D) 11



Geometry - math practice fourth grades:

9) What is the perimeter of the square whose side is 6?

A) 36

B) 12

C) 6

D) 24

10) What is the dimension of the line?

A) One

B) Two

C) three

D) Zero

what is the dimension of  the square?

A) One

B) Two

C) three

D) Zero


Answer key:


1) D

2) B

3) C

4) B

5) A

6) B

7) A

8) C

9) D

10) A

11) B

Friday, May 17, 2013

8th Grade Math Practice Learning

Introduction to 8th grade math practice learning:

Mathematics is a study of basic math operations and maths functions. Mathematics is one of a language and logic thing of a science. It is an essential tool for science, medicine and the geography fields. In mathematics concept a fundamental concept is arithmetic operations. In 8th grade mathematics includes algebra, number system, measurements, geometry, etc. In this article we shall discuss for 8th grade math practice learning.

I like to share this Square Root Word Problems with you all through my article.

Sample problem for 8th grade math practice learning:


8th grade math practice learning problem 1:

Solve the given algebra sample equation and find out m and n value of the equation.

4m + 6n – 10 = 0

-4m + 18n – 14 = 0

Solution:

We are going to find out the m and n value of the given algebra 1 linear equation.

4m + 6n = 10

-4m + 18n = 14

In the first we are going to add equation (1) and (2). We get

4m + 6n = 10

-4m + 18n = 14

0m + 24n = 24

n = 1

Now, we get the n value as 1. In the equation (2) we substitute n = 1, we get

-4m + 18(1) = 14

-4m + 18 = 14

-4m = -4

M = 1

Now, we get the m value as 1. So, the given system of linear equation values are m = 1, n = 1.

8th grade math practice learning problem 2:

Solve the given algebra equation and find out the ‘p’ value 3 - 2(4p - 5) = 5

Solution:

Given:

3 - 2(4p - 5) = 5

We are going to find ‘p’ value of the given equation. Subtract 3 on both side of the equation, we get

3 - 2(4p - 5) - 3 = 5 - 3

-8p + 10 = 2

In the next step grouping the terms, we get

-8p = 2 - 10

-8p = -8

p = 1

8th grade math practice learning problem 3:

Simplify a given algebraic expression: 4p + 6q - 8 + 5p + 6q + 7.

Solution:

We are going to find a value of the given algebraic expression.

4p and 5p are like terms, and can be combined to give 9p,

6q and 6q combine to give 12q, and

-8 and 7 combine to give -1.

In the next we add all the terms, we get 9p+ 12q - 1.

8th grade math practice learning problem 4:

Find a diameter value from a given circle radius. A given circle radius is 5 cm.

Solution:

Given:

Radius of the circle is r = 5 cm

Diameter of the circle is d = 2r

d = 2 * 5

d = 10

So, the diameter of the circle is 10 cm2.

Practice problem for 8th grade math practice learning:

Find the value of the given equation 4m + 26 = 10

Answer: m = -4

Solve the given algebraic equation and find the ‘n’ value 2n -3 = 7.

Answer: n = 5

Find a diameter value from a given circle radius. A given circle radius is 3 cm.

Answer: d = 6 cm2

Algebra 1 Final Exam Practice

Introduction to algebra 1 final exam practice:

Let us see about algebra connections equations. The algebra is a mathematics that can be studied in words of mathematics numbers. In this we learn about the algebra connections equations with a few concepts. The algebra is the branch in which we learned the arithmetical functions, polynomials, factors and some equations. Let us see some examples in  algebra 1 final exam practice.

Important Concepts of Algebra

The followings are some of the algebra concepts.

1. Polynomial

In algebra connections, a polynomial of degree one is known as a linear polynomial.

2. Quadratic equation

In algebra connections, a quadratic equations in a variable of the x .An equation in the form ax2 + bx + c = 0.

3. Algebraic identities

The form (a + b)2 = a2 + 2ab + b2 is called as the algebraic identities.

4. Algebraic expressions

It is a division of polynomial can be denoted by a letters and exponent.


Examples to understand algebra 1 final exam practice:


Algebra Connections Problems

1)Solve the following equation 49x2 – 36 = 0.

Solution:

49x2 – 36 = 0 or

(7x + 6) (7x – 6) = 0 or (by simplify the equations)

7x2- 62 =0

7x2- 36 = 0

x2= 36/7

The solution set = `6 / sqrt 7`

2) Conclude whether (x–3) is a cause of polynomial p(x) = x³ – 3x² + 5x – 15.

Solution:

For (x–3) is a factor of p(x),

p(3) must be zero by the factor theorem.

Now p(3) = 3³ – 3(3) ² + 5(3) – 15

= 27 – 27 + 15 – 15 (by equating the known polynomial)

= 0

Hence (x–3) is a factor of the given polynomial.

3) Calculate 105 * 104 without multiplying directly.

Solution:

105 * 106 = (100 + 5) * (100 + 4)

= (100)² + (4 + 4) (100) + (5 * 4) (by using identity)

= 10000 + 800 + 20

= 10820.

4) Expand: (3a + 2b – 3c) ²

Solution:

Comparing the given expression (3a + 2b – 3c)² with (a + b + c) ²,

From the expression we have,

a = 3a

b = 2b

c = -3c

(3a + 2b – 3c) ² = (3a) ²+ (2b) ² - (3c) ²+ 2(3a) (2b) + 2(2b)(-3c) + 2(-3c)(3a)

Therefore, the equation becomes as,

= 9a² + 4b² + 9c² + 12ab² -12bc -18ca.

These are the examples of algebra connections equations.

I have recently faced lot of problem while learning Solving System of Inequalities, But thank to online resources of math which helped me to learn myself easily on net.

Exam questions to practice for algebra 1 final exam practice:

Problem 1:

Solve the equation 6x + 8 = 38 for x.

Answer: 5

Problem 2:

Solve the equation 8x + (40 ÷ 8) = 53 for x.

Answer: x = 6

Problem 3:

Solve the equation for x2 + 8= 89 for x.

Answer: x = 9

Problem 4:

Solve the equation 5x2 + 15x + 10 = 0 by using quadratic formula.

Answer: x1 = -1 and x2 = -2

Problem 5:

Solve the equation 5x2 + 15x + 10 = 0 by using factorizing method.

Answer: x1 = -1 and x2 = -2

Problem 6:

Solve the equation 3x2 + 4x + 1 = 0 by using quadratic formula.

Answer: x1 = -0.3 and x2 = -1

Problem 7:

Solve the equation 3x2 + 4x + 1 = 0 by using factorizing method.

Answer: x1 = -0.3 and x2 = -1

These are algebra 1 final exam practice as for exam preparation.

Plane Geometry Practice

Introduction for plane geometry practice:

In this branch of mathematics,we study to measure a line segment, find the area of a plane surface and perimeter and the volume of solids.Proper units are chosen for different measurements. In this chapter we will derive standard formula for calculating area of the rectangle, the perimeter of a rectangle,the area of a square of a geometry practice problem.


Area and perimeter of plane geometry practice:

Area of a rectangle = length × breadth

A = l × b

perimeter of a rectangle = 2 lengths + 2 breadths

P = 2l + 2b

Area of a square = side × side

A = a2

Perimeter of a square = 4 × side

P = 4a




Examples for plane geometry practice problems:


Example 1:

Find (a) area and (b) perimeter of a square whose sides is 15 cm.

Solution :

(a) Side of the square, a = 15 cm

Area of the square, A = a2

= a × a

= 15 × 15

= 225 sq.cm (or 225 cm2)

(b) Perimeter of the square, P = 4a

= 4 × 15 cm

= 60 cm

Example 2:

Find the area and perimeter of a rectangle whose length is 4m and breadth is 50 cm.

Solution :

Length of the rectangle, l = 4 m or 400 cm

Breadth of the rectangle, b = 50 cm

(a) Area of the rectangle, A = l × b

= 400 cm × 50 cm

? Area = 20,000 sq.cm.

(b) Perimeter of the rectangle, P = 2l + 2b

= 2 × 400 cm + 2 × 50 cm

= 800 cm + 100 cm

? Perimeter = 1,000 cm

Example 3 :

The perimeter of the floor of a rectangular hall is 24 m. Its rectangle length is 9 meter. Find its area of rectangle.

Note : To find area we should know the measurements of length and breadths. Here rectangle  length is given.

Hence we should find the breadths from the perimeter.

Solution :

2 length + 2 breadth = perimeter

2 × 9 + 2b = 24

18 + 2b = 24

2b = 24 – 18

2 b = 6

b =6/2 = 3

Now the area of the rectangle A = l b

= 9 m × 3 m

= 21 sq.m.

I have recently faced lot of problem while learning Pentagonal Prism Volume Formula, But thank to online resources of math which helped me to learn myself easily on net.

Practice problem for plane geometry :


Find the cost of fencing a rectangular park of lengths 170 m and breadth 100 m at the rate of Rs.9 per metre.

Answer:Rs.2800