8th Grade Math Practice Learning

Introduction to 8th grade math practice learning:

Mathematics is a study of basic math operations and maths functions. Mathematics is one of a language and logic thing of a science. It is an essential tool for science, medicine and the geography fields. In mathematics concept a fundamental concept is arithmetic operations. In 8th grade mathematics includes algebra, number system, measurements, geometry, etc. In this article we shall discuss for 8th grade math practice learning.

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Sample problem for 8th grade math practice learning:


8th grade math practice learning problem 1:

Solve the given algebra sample equation and find out m and n value of the equation.

4m + 6n – 10 = 0

-4m + 18n – 14 = 0

Solution:

We are going to find out the m and n value of the given algebra 1 linear equation.

4m + 6n = 10

-4m + 18n = 14

In the first we are going to add equation (1) and (2). We get

4m + 6n = 10

-4m + 18n = 14

0m + 24n = 24

n = 1

Now, we get the n value as 1. In the equation (2) we substitute n = 1, we get

-4m + 18(1) = 14

-4m + 18 = 14

-4m = -4

M = 1

Now, we get the m value as 1. So, the given system of linear equation values are m = 1, n = 1.

8th grade math practice learning problem 2:

Solve the given algebra equation and find out the ‘p’ value 3 - 2(4p - 5) = 5

Solution:

Given:

3 - 2(4p - 5) = 5

We are going to find ‘p’ value of the given equation. Subtract 3 on both side of the equation, we get

3 - 2(4p - 5) - 3 = 5 - 3

-8p + 10 = 2

In the next step grouping the terms, we get

-8p = 2 - 10

-8p = -8

p = 1

8th grade math practice learning problem 3:

Simplify a given algebraic expression: 4p + 6q - 8 + 5p + 6q + 7.

Solution:

We are going to find a value of the given algebraic expression.

4p and 5p are like terms, and can be combined to give 9p,

6q and 6q combine to give 12q, and

-8 and 7 combine to give -1.

In the next we add all the terms, we get 9p+ 12q - 1.

8th grade math practice learning problem 4:

Find a diameter value from a given circle radius. A given circle radius is 5 cm.

Solution:

Given:

Radius of the circle is r = 5 cm

Diameter of the circle is d = 2r

d = 2 * 5

d = 10

So, the diameter of the circle is 10 cm2.

Practice problem for 8th grade math practice learning:

Find the value of the given equation 4m + 26 = 10

Answer: m = -4

Solve the given algebraic equation and find the ‘n’ value 2n -3 = 7.

Answer: n = 5

Find a diameter value from a given circle radius. A given circle radius is 3 cm.

Answer: d = 6 cm2