Wednesday, January 30, 2013

3rd Grade Maths

Introduction to 3rd grade maths:

3rd grade mathematics covers operations like addition, subtraction, multiplying and division the numbers. They also learn the word problem of addition, subtraction, multiplying and division,four digit numbers and their place values, successor and predecessor etc. We will see some examples from 3rd grade mathematics.

Tutoring on Addition for 3rd Grade Math Homework

Like two digit numbers we will start to add the numbers from left side. First, we will add ones, then tens, then hundred and at last thousand.

Example: 2 4 5 6

+ 2 5 6 3

5 0 1 9

Home work for practice:

(a)    4915 + 3456 =

(b)   2456 + 6754 =

(c)    1345 + 4326 =

(d)    1298 + 4264 =

(e)     3427 + 6743 =

Answer: (a) 8371 (b) 9210 (c) 5671 (d) 5562 (e) 10170

Word problems:

(a) In a city there are 140 shops of toys, 200 shops of grossary items and 300 shops of fancy dresses. Find out the total number of shops?

(b)   A shopkeeper sold 700 greeting cards in one year and 650 cards in the next year.     How many cards did he sell in two years?

Solution: (a) Number of toy shops in a city = 140

Number of grossary shops        = 200

Number of fancy dresses shops = 300

The total number of shops are = 140 + 200 + 300

= 640 shops Ans.

Solution (b) Number of greeting cards sold in one year = 700

Number of greeting cards sold in next year = 650

The total number of cards sold in two years = 700 + 650 = 1350

1350 cards Ans.

Tutoring on Subtraction for 3rd Grade Math Homework

To subtract the numbers, always subtract lowest number from the highest number.

Example: Subtract 214 5 from 5478

5 4 7 8

- 2 1 4 5

3 3 3 3

Home work practice:

(a)    5675 – 3241 =

(b)   3678 – 1625 =

(c)    6666 – 2323 =

(d)   9567 – 2235 =

(e)    7 883 – 2378 =



Answer: (a) 2434 (b) 2053 (c) 4343 (d) 7332 (e) 5505

Word problems :

(a) The cost of one bicycle is 2000 and other bicycle is 4500. What is the difference between their cost?

(b) What should be added to 2340 to get 5000?

Answer: (a) Cost of one bicycle is = 2000

Cost of other bicycle is = 4500

Difference between their costs = 4500 – 2000

= 2500 Ans.

(c)    First we subtract 2340 from 5000

5000 – 2340 = 2660

2340 – 2660 = 5000

Number should be added 2660 Ans.

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