Fraction Ruler for School

Introduction to fraction ruler for school:
In this article we are going to discussing about solving ruler for school fraction problems. Fraction represents the two numbers. The numerator is called the top number. The denominator is called the bottom number. The school fraction solving ruler and examples and practice fraction problems with solution are given below. I like to share this Fractions Tutorial with you all through my article.

Fraction Ruler for School:

Rule 1:

Addition fractions with same (bottom numbers) denominators: directly add the (top number) numerators. In addition, keep the same (bottom number) denominators.

Rule 2:

Addition fractions with different (bottom number) denominators: First, we find the common denominator of this problem, and then add the (top number) numerators. In addition, keep the common denominators.

Rule 3:

Subtraction fractions with same (bottom number) denominators: directly subtract the (top number) numerators. In subtraction, keep the same denominators.

Rule 4:

Subtraction fractions with different (bottom number) denominators: First, we find the common denominator of this problem, and then subtract the (top number) numerators. In subtraction, keep the common denominators.

Rule 5:

Multiply fractions: multiply the two or more fractions mean we do not need the same (bottom number) denominators. Directly multiply both (top number) numerators and denominators.Please express your views of this topic Simple Interest Problems by commenting on blog.

Fraction Ruler for School – Example Problems:

Example 1:

Add the fractions for given two fraction, `4/8` + `3/8`

Solution:

The given two fractions are `4/8` + `3/8`0

The same denominators of the two fractions, so

= `4/8` + `3/8`

Add the numerators the 4 and 3 = 4+3 = 7.

The same denominator is 8.

= `7/8`

The addition fraction solution is `7/8` .

Example 2:

Subtract the fractions for given two fractions `4/6` - `6/5`

Solution:

The denominator (bottom number) is different so we take a (lcd) least common denominator

LCD = 6 x 5 = 30

So multiply and divide by 5 in first term we get

` (4 xx 5) / (6 xx 5)`

=`20/30`

Multiply and divide by 6 in second terms

= `(6 xx 6) / (5 xx 6)`

= `36/30`

The denominators are equals

So subtracting the numerator directly = `(20-36)/30`

Simplify the above equation we get = `-16/30`

Therefore the final answer is `-8/15`

Fraction ruler for school – practice problems:

Problem 1: Add `1/5 ` + `2/5`

Problem 2: Sub `5/8 ` – ` 3/8`

Fraction ruler for school – answer key:

Problem 1: `3/5`

Problem 2: `1/4`

Factoring Fractional Exponents

Introduction to factoring:

In mathematics, a rational function is any function which can be written as the ratio of two polynomial functions. Factorization (also factorization in British English) or factoring is the decomposition of an object (for example, a number, a polynomial, or a matrix) into a product of other objects, or factors, which when multiplied together give the original.

Example Problems for Factoring Fractional Exponents

Factoring fractional exponents example problem 1:

Factoring the given fractional expression `(1 / 3)` x^2 - `(11 / 3)` x - 144 = 0

Solution:

Given fractional expression is `(1 / 3)` x^2 - `(11 / 3)` x - 144 = 0

Multiply the given expression by 3 on both the sides, we get

x^2 - 11x - 432 = 0

Factorize the above equation, we get

x^2 - 27x + 16x - 432 = 0

Grouping the first two terms and second terms, we get

(x^2 - 27x) + (16x - 432) = 0

Take common terms, we get

x (x - 27) + 16 (x - 27) = 0

(x - 27) (x + 16) = 0

The factors of the given fractional expression is (x - 27) and (x + 16)

Answer:

The final answer is (x - 27) and (x + 16)

Factoring fractional exponents example problem 2:

Factoring the given fractional expression `(1 / 5)` x^2 - `(27 / 5)` x - 74 = 0

Solution:

Given fractional expression is `(1 / 5)` x^2 - `(27 / 5)`x - 74 = 0

Multiply the given expression by 5 on both the sides, we get

x^2 - 27x - 370 = 0

Factorize the above equation, we get

x^2 - 37x + 10x - 370 = 0

Grouping the first two terms and second terms, we get

(x^2 - 37x) + (10x - 370) = 0

Take common terms, we get

x (x - 37) + 10 (x - 37) = 0

(x - 37) (x + 10) = 0

The factors of the given fractional expression is (x - 37) and (x + 10)

Answer:

The final answer is (x - 37) and (x + 10)

Factoring fractional exponents example problem 3:

Factoring the given fractional expression `(1 / 7)`x^2 - `(12 / 7)`x + 5 = 0

Solution:

Given fractional expression is `(1 / 7)`x^2 - `(12 / 7)`x + 5 = 0

Multiply the given expression by 7 on both the sides, we get

x^2 - 12x + 35 = 0

Factorize the above equation, we get

x^2 - 7x - 5x + 35 = 0

Grouping the first two terms and second terms, we get

(x^2 - 7x) - (5x - 35) = 0

Take common terms, we get

x (x - 7) - 5 (x - 7) = 0

(x - 7) (x - 5) = 0

The factors of the given fractional expression is (x - 7) and (x - 5)

Answer:

The final answer is (x - 7) and (x - 5)

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Practice Problems for Factoring Fractional Exponents

Factoring fractional exponents practice problem 1:

Factoring the given fractional expression `(1 / 24)`x^2 + `(23 / 24)`x - 12 = 0

Answer:

The final answer is (x + 32) and (x - 9)

Factoring fractional exponents practice problem 2:

Factoring the given fractional expression `(10 / 7)`x^2 - `(59 / 7)`x + 7 = 0

Answer:

The final answer is (10x - 49) and (10x - 10)