Showing posts with label The Mean. Show all posts
Showing posts with label The Mean. Show all posts

Sunday, March 24, 2013

Statistics Practice Exam

Introduction to statistics practice exam:

Statistics is the science of making effective use of numerical data relating to groups of individuals or experiments. It deals with all aspects of this, including not only the collection, analysis and interpretation of such data, but also the planning of the collection of data, in terms of the design of surveys and experiments.

A statistician is someone who is particularly versed in the ways of thinking necessary for the successful application of statistical analysis. Often such people have gained this experience after starting work in any of a number of fields. There is also a discipline called mathematical statistics, which is concerned with the theoretical basis of the subject.

Let us see several statistics based solved problems and statistics practice exam. Statistics practice exam with solutions which would be helpful for students to evaluate their performance.

Concepts on statistics practice exam:


Before going for a statistics practice exam, let us recall how to find mean deviation. The steps to find the mean deviation are as follows.

Step 1: find the mean for given data
`barx` = (sum of all variables) /( given number of  variables).

Step 2: find the deviation of the respective observations from mean `barx` ,  in other words  xi -  `barx`
Step 3: find the modulation of deviation ,     | Xi - `barx` |
Step 4: mean deviation of the mean,
M.D.(`barx` ) = `sum` n i-1 | xi - x| / n

Example1:

Find the mean deviation about the mean for the following data:

12, 5, 16, 14, 11, 5, 10, 15

Solution:

We proceed step-wise and get the following:

Step 1 Mean of the given data is `barx`

`barx`  = `(12+5+16+14+11+5+10+15)/8` = `88/8` = 11

Step 2 The deviations of the respective observations from the mean x, i.e., xi – x are

12–11,5–11,16–11,14–11,11–11,5–11,10–11,15–11,

or 1,–6,5,3,0,–6,–1,4

Step 3 The absolute values of the deviations, i.e.,|xi − x |are

1,6,5,3,0,6,1,4

Step 4 The required mean deviation of the mean is

M.D. (`barx`   ) =`sum` 8 i-1 |xi-x| / 8

=`(1+6+5+3+0+6+1+4)/8` = `26/8` = 3.25.

Example2:

Find the mean deviation about the mean for the following data:

15, 5, 12, 16, 12, 4, 9, 16,7.

Solution:

We proceed step-wise and get the following:

Step 1 Mean of the given data is `barx`

`barx`  = `(15+5+12+16+12+7+9+16+7)/9` = `99/9` = 11

Step 2 The deviations of the respective observations from the mean x, i.e., xi – x are

15–11,5–11,12–11,16–11,12–11,7–11,9–11,16–11,7-11.

or 4,–6,1,5,1,–4,–2,5,-4

Step 3 The absolute values of the deviations, i.e.,|xi − x |are

4,6,1,5,1,4,2,5,4

Step 4 The required mean deviation of the mean is

M.D. (`barx`   ) =`sum` 8 i-1 |xi-x| / 8

=`(4+6+1+5+1+4+2+5+4)/8` = `32/8` = 4.

I have recently faced lot of problem while learning Complementary Events, But thank to online resources of math which helped me to learn myself easily on net.

Practice on statistics practice exam:

Statistics Practice exam:

1. Find the mean deviation for the mean of the following data:
6, 7, 10, 12, 13, 4, 8, 12

2. Find the mean deviation for the mean of the following data :
12, 3, 18, 17, 4, 9, 17, 19, 20, 15, 8, 17, 2, 3, 16, 11, 3, 1, 0, 5

Answers for the above questions of statistics practice exam:

1.   2 75

2.   6.2