Introduction to practice algebra class:
Algebra class deals with the Pre-algebra, Functions and Graphs, Integers, Rational Numbers, Equations in One Variable, Equations in Two Variables, Simultaneous Equations, Problem Solving etc. in arithmetic, we use digit like 1,2,3, etc to represent numbers. In algebra we use numbers as well as letters of the alphabet such as a, b, c, etc for any numerical values we choose. The basic thought of the algebra is balancing the algebraic equations on both sides of the give equations in the problems. Algebra will perform the four fundamental operations such as addition, subtraction, multiplication and division. In this article we shall discuss with practice algebra class
Sample problem on practice algebra class
Problems of algebra class on linear equations:
Example 1:
Solve the linear equation for algebra class
11 x - 15 = 19 x - 23
Solutions:
11 x - 15 = 19 x - 23
Subtract 19 x from both sides of the above equation, we get the below term
-8x – 15 = -23
Add 15 to both sides of the above equation, we get the below term
-8x – 15 + 15 = - 23 + 15
-8x = - 8
Divide both sides by -8 of the equation, we get
X = 1
The answer is x = 1
Test the solution for the given equation. Replace with in the above given equation for x. If the left side of the equation sum value is equal to the right side of the equation sum value after the replacement of x value, you have got the exact answer.
Left side of the equation:
11(1) - 15 = - 4
Right side of the equation:
19(1) - 23 = - 4
Practice word problems of algebra class
Example 2:
A bag contains ten, five and two rupees currencies. The total number of Currencies is 30 and the total value of money is Rs.135. If the second and third currencies are interchanged the value will decrease Rs.8. Find the number of currency in each sort.
Solution :
Let x, y, z be the number of Rs.10, Rs.5 and Rs.2 currencies respectively.
The total number of currencies is 30 => x + y + z = 30--------(1)
If the total value of money is Rs.135 => 10x + 5y + 2z = 136--------(2)
If the II and III of currencies are interchange the value will be decreased by Rs.8
=>10x + 2y + 5z = 135 – 8 = 127----------------(3)
10x + 2y + 5z = 127
10 x (1) – (2) => 5y + 8z = 106------------(4)
(2) – (3) => 3y - 3z = 9
y – z = 3------------------(5)
Let us solve (4) and (5)
(4) => 5y + 8z = 106
8 x (5) ⇒ 8y – 8z = 24
13y = 130
y = 10
Substituting y = 10 in (5) we get
z = 7
Substituting z = 7, y = 10 in (1) we get
x + 10 + 7 = 30 => 30 – 10 – 7 or x = 13
Number of Rs.10, Rs.5 and Rs.2 currencies are respectively 13, 10 and 7.
Is this topic Fraction to Decimal Calculator hard for you? Watch out for my coming posts.
Practice problem for algebra class:
Problem 1:
2x + 11 = 20 - x
Answer: x = 3
Problem 2:
7x + 11 = 19 + 3x
Answer: x = 2
Algebra class deals with the Pre-algebra, Functions and Graphs, Integers, Rational Numbers, Equations in One Variable, Equations in Two Variables, Simultaneous Equations, Problem Solving etc. in arithmetic, we use digit like 1,2,3, etc to represent numbers. In algebra we use numbers as well as letters of the alphabet such as a, b, c, etc for any numerical values we choose. The basic thought of the algebra is balancing the algebraic equations on both sides of the give equations in the problems. Algebra will perform the four fundamental operations such as addition, subtraction, multiplication and division. In this article we shall discuss with practice algebra class
Sample problem on practice algebra class
Problems of algebra class on linear equations:
Example 1:
Solve the linear equation for algebra class
11 x - 15 = 19 x - 23
Solutions:
11 x - 15 = 19 x - 23
Subtract 19 x from both sides of the above equation, we get the below term
-8x – 15 = -23
Add 15 to both sides of the above equation, we get the below term
-8x – 15 + 15 = - 23 + 15
-8x = - 8
Divide both sides by -8 of the equation, we get
X = 1
The answer is x = 1
Test the solution for the given equation. Replace with in the above given equation for x. If the left side of the equation sum value is equal to the right side of the equation sum value after the replacement of x value, you have got the exact answer.
Left side of the equation:
11(1) - 15 = - 4
Right side of the equation:
19(1) - 23 = - 4
Practice word problems of algebra class
Example 2:
A bag contains ten, five and two rupees currencies. The total number of Currencies is 30 and the total value of money is Rs.135. If the second and third currencies are interchanged the value will decrease Rs.8. Find the number of currency in each sort.
Solution :
Let x, y, z be the number of Rs.10, Rs.5 and Rs.2 currencies respectively.
The total number of currencies is 30 => x + y + z = 30--------(1)
If the total value of money is Rs.135 => 10x + 5y + 2z = 136--------(2)
If the II and III of currencies are interchange the value will be decreased by Rs.8
=>10x + 2y + 5z = 135 – 8 = 127----------------(3)
10x + 2y + 5z = 127
10 x (1) – (2) => 5y + 8z = 106------------(4)
(2) – (3) => 3y - 3z = 9
y – z = 3------------------(5)
Let us solve (4) and (5)
(4) => 5y + 8z = 106
8 x (5) ⇒ 8y – 8z = 24
13y = 130
y = 10
Substituting y = 10 in (5) we get
z = 7
Substituting z = 7, y = 10 in (1) we get
x + 10 + 7 = 30 => 30 – 10 – 7 or x = 13
Number of Rs.10, Rs.5 and Rs.2 currencies are respectively 13, 10 and 7.
Is this topic Fraction to Decimal Calculator hard for you? Watch out for my coming posts.
Practice problem for algebra class:
Problem 1:
2x + 11 = 20 - x
Answer: x = 3
Problem 2:
7x + 11 = 19 + 3x
Answer: x = 2
