Introduction of monomial functions :
A term is a variable or a number (which is constant) or a variable with a
number attached (called a co-efficient). A single tem is called a monomial.
Monomial can be written as f(x) = C (or) f(x) = C. x n
Where n is a positive integer
k is a constant
How to Solve Monomial Functions:
- To add monomial
You can only add monomial that has the same base. If the bases are same, then
we can add their co-efficient.
- To subtract monomial
Like in addition, for subtraction also the monomial should be of same bases.
The co-efficient is subtracted then.
- To multiply monomial
If there are coefficients on the terms then we must first multiply coefficients
by coefficients. Then we can multiply the variable of one term by the other.
- To divide monomial
When we divide the monomial, remember that the numerical coefficients are
divided and then the literal coefficients (such as a and b).
Sample Problems for Monomial Functions:
Pro 1: Add the following monomial 5x, 2y, 3x
= (5x + 3x) + 2y
= 8x + 2y
Pro 2 : Add the monomial 3x3+ 2y3, 3xy, 2xy, 3y3
Sol : 3x3 + 2y3 + 3xy + 2xy + 3y3
3x3 + 2y3 +
3xy + 2xy + 3y3
3x3 + 5y3 + 5xy
Pro 3: Subtract the following: 2x from 5x
Sol : The bases are same. Hence we can subtract
= 5x – 2x
= 3x
Pro 4: Solve monomial 3x3 + 2y3- 3xy-2xy- 3y3
Sol : = 3x3 + 2y3 - 3xy - 2xy - 3y3
= 3x3 – 5xy - y3
Pro 5 : Multiply the following monomial: (3x)(4y)
Sol : First multiply the coefficients
(3)(4) = 12
Then
multiply the variables
(x)(y) = xy
So the answer is:
12xy
Pro 6 : Multiply the following monomial: (8x3)(2x5)
Sol : First multiply the coefficients
(8)(2) = 16
Multiplying the variables
Multiplying the variables
(x3)(x5)
= (x3+5) = x8
So the
answer is 16x
Pro 7 : Divide 4ax by 2ay
Sol : First: 4 / 2 = 2
Second: ax / ay =
x/y
The
solution is 2x/y
Pro 8 : Divide (2a2 bc) by (4ac)
Sol : First: 2/4 = 1/2
Second: a2 bc
/ ac = ab
The
solution is (1/2) ab = ab / 2