Showing posts with label monomial functions. Show all posts
Showing posts with label monomial functions. Show all posts

Thursday, August 23, 2012

Introduction of monomial functions


Introduction of monomial functions :

A term is a variable or a number (which is constant) or a variable with a number attached (called a co-efficient). A single tem is called a monomial. Monomial can be written as f(x) = C (or) f(x) = C. x n

Where n is a positive integer

k is a constant

How to Solve Monomial Functions:
  • To add monomial
You can only add monomial that has the same base. If the bases are same, then we can add their co-efficient.
  • To subtract monomial
Like in addition, for subtraction also the monomial should be of same bases. The co-efficient is subtracted then.
  • To multiply monomial
If there are coefficients on the terms then we must first multiply coefficients by coefficients. Then we can multiply the variable of one term by the other.
  • To divide monomial
When we divide the monomial, remember that the numerical coefficients are divided and then the literal coefficients (such as a and b).

Please express your views of this topic algebra2 word problems by commenting on blog

Sample Problems for Monomial Functions:

Pro 1:  Add the following monomial 5x, 2y, 3x

Sol :    Here we have two different terms x and y. We can add only the coefficients of same monomial.
            = (5x + 3x) + 2y
            = 8x + 2y

Pro 2 :  Add the monomial 3x3+ 2y3, 3xy, 2xy, 3y3

Sol :     3x3 + 2y3 + 3xy + 2xy + 3y3
            3x3 + 2y3 + 3xy + 2xy + 3y3
            3x3 + 5y3 + 5xy

Pro 3:   Subtract the following: 2x from 5x

Sol :    The bases are same. Hence we can subtract
            = 5x – 2x
            = 3x

Pro 4:   Solve monomial 3x3 + 2y3- 3xy-2xy- 3y3

Sol :      = 3x3 + 2y3 - 3xy - 2xy - 3y3
             = 3x– 5xy - y3

Pro 5 :  Multiply the following monomial: (3x)(4y)

Sol :    First multiply the coefficients
    (3)(4) = 12
   Then multiply the variables
   (x)(y) = xy
  So the answer is: 12xy

Pro 6 :  Multiply the following monomial: (8x3)(2x5)

Sol :    First multiply the coefficients
      (8)(2) = 16

    Multiplying the variables
      (x3)(x5) = (x3+5) = x8
   So the answer is 16x

Pro 7 :   Divide 4ax by 2ay

Sol :    First: 4 / 2 = 2
  Second: ax / ay = x/y
   The solution is 2x/y

Pro 8 :  Divide (2a2 bc) by  (4ac)

Sol  :    First: 2/4 = 1/2
      Second: a2 bc / ac = ab
     The solution is (1/2) ab = ab / 2